jquery日期选择,jquery日期选择控件

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Jquery 日期控件，怎么只选择和显示当天和时间

日期对象可以使用系统的内置的构造函数来创建日期对象:

var d=new Date( );

d.getYear( ); //返回年不建议使用

d.getFullYear( ); //返回年,4位数,建议使用

d.getMonth( );//返回月份,其值为0-11;

d.getDate( );//返回返回日期对象中的一个月中的第几天

d.getDay( );//返回星期几中的某一天

d.getHours( );//返回日期对象的小时部分

d.getMinutes( );//返回分钟部分

d.getSeconds( );//返回秒钟

d.getMillSeconds( );//返回毫秒

d.getTime( );//返回时间戳

d.getTimezoneOffset( );//返回时区的时差数,单位是秒

希望对你有用.

jquery ui中的datepicker日期选择，怎么样将当前日期之前的时间设为设为不能选中

Datepicker 的选项中有一个 minDate（最小日期），如果你把 minDate 设为当前日期，之前的日期就都不能选了。

minDate 可以为

1、日期对象，例如 new Date()

2、也可以是整数，例如 3 代表 3 天后，-1 代表昨天，0 代表今天

3、也可以是字符串，例如 1w 代表 1 星期后，-2m 代表两个月之前

所以你的问题，可以设置为日期对象（当前）或者0。

$("#ele").datepicker({

minDate: new Date()

});

或者

$("#ele").datepicker({

minDate: 0

});

jquery日期选择控件怎么写

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c.elem[h.elemv]="",c.msg("日期不在有效期内，请重新选择。"),1;f.value=c.elem[h.elemv].match(b).join(),e=f.value.match(/\d+/g),e[1]1?(e[1]=1,f.auto=1):e[1]12?(e[1]=12,f.auto=1):e[1].length2(f.auto=1),e[2]1?(e[2]=1,f.auto=1):e[2]c.months[(0|e[1])-1]?(e[2]=31,f.auto=1):e[2].length2(f.auto=1),e.length3(c.timeVoid(e[3],0)(f.auto=1),c.timeVoid(e[4],1)(f.auto=1),c.timeVoid(e[5],2)(f.auto=1)),f.auto?c.creation([e[0],0|e[1],0|e[2]],1):f.value!==c.elem[h.elemv](c.elem[h.elemv]=f.value)}},c.months=[31,null,31,30,31,30,31,31,30,31,30,31],c.viewDate=function(a,b,d){var f=(c.query,{}),g=new Date;a(0|c.mins[0])(a=0|c.mins[0]),a(0|c.maxs[0])(a=0|c.maxs[0]),g.setFullYear(a,b,d),f.ymd=[g.getFullYear(),g.getMonth(),g.getDate()],c.months[1]=c.isleap(f.ymd[0])?29:28,g.setFullYear(f.ymd[0],f.ymd[1],1),f.FDay=g.getDay(),f.PDay=c.months[0===b?11:b-1]-f.FDay+1,f.NDay=1,c.each(h.tds,function(a,b){var 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