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关于c语言中用于txt的函数的信息
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关于C语言中读取TXT文本的内容
1通过fopen函数打开文本，例如file
*fp=fopen("in.txt","r");//返回一个file类型的句柄
2然后就可以通过fcanf()函数对txt文本进行读取
3操作完文本之后用fclose()函数
关闭已经打开的文件。
#include
int main()
{
int data;
file *fp=fopen("in.txt","r");
if(!fp)
{
printf("can't open file\n");
return -1;
}
while(!feof(fp))
{
fscanf(fp,"%d",data);
printf("%4d",data);
}
printf("\n");
fclose(fp);
return 0;
}
C语言如何读取txt文本里面的内容？
C语言可以使用fopen（）函数读取txt文本里。
示例：
#include stdio.h
FILE *stream, *stream2;
void main( void )
{
int numclosed;
/* Open for read (will fail if file "data" does not exist) */
if( (stream = fopen( "data", "r" )) == NULL )
printf( "The file 'data' was not opened\n" );
else
printf( "The file 'data' was opened\n" );
/* Open for write */
if( (stream2 = fopen( "data2", "w+" )) == NULL )
printf( "The file 'data2' was not opened\n" );
else
printf( "The file 'data2' was opened\n" );
/* Close stream */
if(fclose( stream2 ))
printf( "The file 'data2' was not closed\n" );
/* All other files are closed: */
numclosed = _fcloseall( );
printf( "Number of files closed by _fcloseall: %u\n", numclosed );
}
扩展资料
使用fgetc函数
#include stdio.h
#include stdlib.h
void main( void )
{
FILE *stream;
char buffer[81];
int i, ch;
/* Open file to read line from: */
if( (stream = fopen( "fgetc.c", "r" )) == NULL )
exit( 0 );
/* Read in first 80 characters and place them in "buffer": */
ch = fgetc( stream );
for( i=0; (i 80 ) ( feof( stream ) == 0 ); i++ )
{
buffer[i] = (char)ch;
ch = fgetc( stream );
}
/* Add null to end string */
buffer[i] = '\0';
printf( "%s\n", buffer );
fclose( stream );
}
C语言用什么函数 读取txt
写几段代码就是了
char s[100];
FILE *fp;
fp=fopen("d:\\1.txt","r");//打开文件，注意是两个\\
gets(s,50,fp);从文件中读取49个字符到s中
