正文
用C语言图形函数画出水果 用c语言画苹果
小程序：扫一扫查出行【扫一扫了解最新限行尾号】
复制小程序
c语言编贪吃蛇，用什么编译环境，怎么显示贪吃蛇和水果，怎么键盘响应？我菜鸟都不算，求指教。
你如果用TC
#includegraphics.h
#includestdlib.h
#define N 200
#define up 0x4800
#define down 0x5000
#define left 0x4b00
#define right 0x4d00
#define esc 0x011b
#define Y 0x1579
#define n 0x316e
int gamespeed; /* 游戏速度 */
int i,key,color;
int score=0; /* 游戏分数 */
char cai48H[]={
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x04,0x00,0x18,0x00,0x00,0x00,0x0E,0x00,
0x1C,0x00,0x00,0x00,0x1C,0x00,0x1C,0x00,
0x00,0x00,0x20,0x00,0x38,0x00,0x00,0x00,
0x40,0x00,0x78,0x00,0x00,0x01,0x80,0x40,
0x70,0x00,0x00,0x03,0x80,0xC0,0xE0,0x00,
0x00,0x07,0x80,0x80,0xC0,0x00,0x00,0x0E,
0x11,0x81,0xC0,0x00,0x00,0x08,0x61,0x01,
0x80,0x00,0x00,0x00,0x23,0x03,0x04,0x00,
0x00,0x02,0x02,0x00,0x06,0x00,0x00,0x1E,
0x04,0x00,0x0F,0x00,0x00,0x1C,0x1F,0x80,
0x1E,0x00,0x00,0x08,0x3F,0x80,0x3C,0x00,
0x00,0x00,0xFF,0x80,0x38,0x00,0x00,0x03,
0xFF,0x80,0x78,0x00,0x00,0x0F,0xF8,0x00,
0xF0,0x00,0x00,0x7F,0xF0,0x00,0xE0,0x00,
0x03,0xFF,0xFC,0x01,0x80,0x00,0x03,0xC0,
0xFF,0x01,0x03,0x80,0x01,0x01,0xFF,0x00,
0x03,0x80,0x00,0x01,0x3F,0x00,0x07,0x80,
0x00,0x02,0x11,0x00,0x07,0x00,0x00,0x00,
0x10,0x00,0x07,0x00,0x00,0x00,0x10,0x00,
0x0E,0x00,0x00,0x08,0x10,0x00,0x1C,0x00,
0x00,0x30,0x10,0x00,0x18,0x00,0x00,0x70,
0x10,0x00,0x30,0x00,0x01,0xE0,0x10,0x00,
0x70,0x00,0x03,0x80,0x10,0x00,0x60,0x00,
0x00,0x00,0x30,0x00,0xE0,0x00,0x00,0x00,
0xF0,0x01,0xC0,0x00,0x00,0x00,0x70,0x03,
0xC0,0x00,0x00,0x00,0x10,0x07,0x80,0x00,
0x00,0x00,0x00,0x0F,0x00,0x00,0x00,0x00,
0x00,0x1E,0x00,0x00,0x00,0x00,0x00,0x3C,
0x00,0x00,0x00,0x00,0x00,0x70,0x00,0x00,
0x00,0x00,0x01,0xC0,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char she48H[]={
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x04,
0x00,0x00,0x00,0x00,0x00,0x0C,0x00,0x00,
0x00,0x00,0x00,0x0E,0x00,0x00,0x00,0x00,
0x00,0x0E,0x00,0x00,0x00,0x03,0x00,0x07,
0x00,0x00,0x00,0x02,0x00,0x03,0x00,0x00,
0x00,0x02,0x00,0x00,0x00,0x00,0x00,0x02,
0x00,0x00,0xF8,0x00,0x00,0x02,0x00,0x07,
0x86,0x00,0x00,0x02,0x00,0x18,0x03,0x00,
0x00,0x02,0x00,0x00,0x07,0x80,0x00,0x03,
0xF0,0x00,0x07,0x80,0x00,0x0F,0xFC,0x00,
0x0C,0x00,0x00,0x7E,0x3F,0x80,0x00,0x00,
0x01,0xFE,0x1F,0x80,0x00,0x00,0x01,0xE2,
0x39,0x8C,0x00,0x00,0x00,0xC2,0x30,0x08,
0x00,0x00,0x00,0xC2,0x60,0x08,0x00,0x00,
0x00,0xC3,0xE0,0x08,0x60,0x00,0x00,0x7F,
0xE0,0x01,0xE0,0x00,0x00,0x3F,0x80,0x1F,
0xE0,0x00,0x00,0x1E,0x00,0x1F,0x80,0x00,
0x00,0x1E,0x00,0x1F,0x00,0x00,0x00,0x02,
0x38,0x1E,0x00,0x00,0x00,0x07,0xFC,0x1C,
0x00,0x20,0x00,0x07,0xFC,0x18,0x00,0x20,
0x00,0x1F,0x0C,0x10,0x00,0x20,0x00,0x7C,
0x04,0x10,0x00,0x60,0x01,0xF0,0x00,0x10,
0x00,0x60,0x01,0xE0,0x00,0x08,0x00,0xF0,
0x00,0x80,0x00,0x08,0x03,0xF0,0x00,0x00,
0x00,0x07,0xFF,0xF0,0x00,0x00,0x00,0x07,
0xFF,0xF0,0x00,0x00,0x00,0x03,0xFF,0xE0,
0x00,0x00,0x00,0x01,0xFF,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char tun48H[]={
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x0E,0x00,0x00,0x00,0x00,0x00,0x3E,
0x00,0x00,0x00,0x00,0x00,0x7F,0x00,0x00,
0x00,0x00,0x00,0xE0,0x00,0x00,0x00,0x00,
0x03,0xC0,0x00,0x00,0x00,0x00,0x1F,0x00,
0x00,0x00,0x00,0x00,0x7C,0x00,0x00,0x00,
0x00,0x01,0xF8,0x00,0x00,0x00,0x00,0x03,
0xF8,0x00,0x40,0x00,0x00,0x00,0x06,0x07,
0xC0,0x00,0x00,0x00,0x07,0xFF,0xE0,0x00,
0x00,0x00,0x07,0xFF,0xE0,0x00,0x00,0x00,
0x0F,0xFF,0x80,0x00,0x00,0x00,0x7F,0xF8,
0x00,0x00,0x00,0x1F,0xFF,0xF8,0x00,0x00,
0x00,0x1F,0xFF,0xF8,0x00,0x00,0x00,0x1F,
0xFC,0x3C,0x00,0x00,0x00,0x0F,0xF8,0x0E,
0x00,0x00,0x00,0x04,0x70,0x07,0x00,0x00,
0x00,0x00,0x60,0x03,0x80,0x00,0x00,0x00,
0xC0,0x00,0xC0,0x00,0x00,0x01,0x80,0x00,
0x30,0x00,0x00,0x01,0x00,0x3C,0x18,0x00,
0x00,0x02,0x03,0xFF,0x0C,0x00,0x00,0x0C,
0x7F,0xFF,0x8E,0x00,0x00,0x18,0xFF,0xFF,
0xC7,0x80,0x00,0x78,0xFE,0x07,0x87,0xE0,
0x01,0xF0,0x70,0x07,0x03,0xF8,0x07,0xE0,
0x70,0x0E,0x03,0xFE,0x00,0x00,0x38,0x1E,
0x01,0xFE,0x00,0x00,0x3F,0xFE,0x00,0x0C,
0x00,0x00,0x1F,0xFE,0x00,0x00,0x00,0x00,
0x1F,0xFE,0x00,0x00,0x00,0x00,0x0F,0xFE,
0x00,0x00,0x00,0x00,0x04,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char dan48H[]={
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0xFC,0x00,0x00,0x00,0x00,0x07,0xFF,
0x00,0x00,0x00,0x00,0x7F,0xC0,0x80,0x00,
0x00,0x03,0xFF,0x80,0x40,0x00,0x00,0x01,
0xF1,0x80,0x40,0x00,0x00,0x01,0x81,0x80,
0xE0,0x00,0x00,0x00,0x01,0x93,0xF0,0x00,
0x00,0x00,0x01,0xFF,0xF0,0x00,0x00,0x00,
0x21,0xFF,0xF0,0x00,0x00,0x00,0x21,0xF8,
0x00,0x00,0x00,0x00,0x61,0xC0,0x00,0x00,
0x00,0x00,0x61,0x80,0x00,0x00,0x00,0x00,
0xF3,0x00,0x00,0x00,0x00,0x00,0xFF,0x00,
0x00,0x00,0x00,0x01,0xFF,0xC0,0x00,0x00,
0x00,0x03,0xFF,0xF8,0x00,0x00,0x00,0x02,
0x00,0xFC,0x00,0x00,0x00,0x04,0x02,0x1F,
0x00,0x00,0x00,0x08,0x03,0x01,0xC0,0x00,
0x00,0x38,0x03,0x00,0x7C,0x00,0x00,0xF8,
0x07,0xF8,0x3F,0xC0,0x01,0xF0,0x3F,0xFE,
0x3F,0xF8,0x03,0xC1,0xFF,0x0F,0x1F,0xF8,
0x00,0x01,0xE3,0x0F,0x0F,0xF0,0x00,0x01,
0xC3,0x0E,0x00,0x00,0x00,0x01,0x83,0xFC,
0x00,0x00,0x00,0x00,0xC7,0xF8,0x00,0x00,
0x00,0x00,0xFF,0xF8,0x00,0x00,0x00,0x00,
0x7F,0xF0,0x00,0x00,0x00,0x00,0x3F,0x03,
0x80,0x00,0x00,0x00,0x03,0x04,0x00,0x00,
0x00,0x00,0x03,0xF8,0x00,0x00,0x00,0x00,
0x1F,0xF8,0x20,0x00,0x00,0x00,0xFF,0xFF,
0xE0,0x00,0x00,0x07,0xFF,0x81,0xE0,0x00,
0x00,0x07,0xE0,0x00,0xE0,0x00,0x00,0x03,
0x00,0x00,0x60,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char zuo16H[]={
0x18,0xC0,0x18,0xC0,0x19,0x80,0x31,0xFE,
0x33,0xFE,0x76,0xC0,0xF0,0xFC,0xB0,0xFC,
0x30,0xC0,0x30,0xC0,0x30,0xFE,0x30,0xFE,
0x30,0xC0,0x30,0xC0,0x30,0xC0,0x00,0x00,
};
char zhe16H[]={
0x03,0x00,0x03,0x0C,0x1F,0xCC,0x1F,0xD8,
0x03,0x30,0xFF,0xFE,0xFF,0xFE,0x03,0x00,
0x0F,0xF8,0x3F,0xF8,0xEC,0x18,0xCF,0xF8,
0x0C,0x18,0x0F,0xF8,0x0F,0xF8,0x00,0x00,
};
char tian16H[]={
0x00,0x00,0x3F,0xFC,0x3F,0xFC,0x31,0x8C,
0x31,0x8C,0x31,0x8C,0x3F,0xFC,0x3F,0xFC,
0x31,0x8C,0x31,0x8C,0x31,0x8C,0x3F,0xFC,
0x3F,0xFC,0x30,0x0C,0x00,0x00,0x00,0x00,
};
char xue16H[]={
0x33,0x18,0x19,0x98,0x08,0xB0,0x7F,0xFC,
0x7F,0xFC,0x60,0x0C,0x1F,0xF0,0x1F,0xF0,
0x00,0xC0,0x7F,0xFC,0x7F,0xFC,0x01,0x80,
0x01,0x80,0x07,0x80,0x03,0x00,0x00,0x00,
};
char ke16H[]={
0x00,0x00,0x0C,0x18,0xFD,0x98,0xF8,0xD8,
0x18,0x58,0xFE,0x18,0xFE,0x98,0x18,0xD8,
0x3C,0x58,0x7E,0x1E,0xDB,0xFE,0x9B,0xF8,
0x18,0x18,0x18,0x18,0x18,0x18,0x00,0x00,
};
struct Food/*定义结构体存储食物的属性*/
{
int x; /* 食物的坐标 */
int y;
int yes; /* 值为0表示屏幕上没有食物，值为1表示屏幕上有食物 */
int color; /* 食物颜色 */
}food;
struct Snake/*定义结构体存储蛇的属性*/
{
int x[N]; /* 每一节蛇的坐标 */
int y[N];
int color[N];/*存储每一节蛇的颜色*/
int node; /* 蛇的节数 */
int direction; /* 蛇移动的方向 */
int life; /* 蛇的生命，如果为1，蛇死，游戏结束 */
}snake;
void init(void)/*图形驱动*/
{
int driver=DETECT,mode=0;
registerbgidriver(EGAVGA_driver);
initgraph(driver,mode,"");
}
void drawmat(char *mat,int matsize,int x,int y,int color)/*汉字点阵*/
{
int i,j,k,m;
m=(matsize-1)/8+1;
for(j=0;jmatsize;j++)
for(i=0;im;i++)
for(k=0;k8;k++)
if(mat[j*m+i](0x80k))
putpixel(x+i*8+k,y+j,color);
}
void showword(void)
{/* 调用汉字点阵输出程序，显示标题和作者信息 */
drawmat(cai48H,48,249,-4,7);
drawmat(she48H,48,329,-4,7);
drawmat(tun48H,48,409,-4,7);
drawmat(dan48H,48,489,-4,7);
drawmat(cai48H,48,250,-5,4);
drawmat(she48H,48,330,-5,4);
drawmat(tun48H,48,410,-5,4);
drawmat(dan48H,48,490,-5,4);
/*作者 田学科*/
drawmat(zuo16H,16,515,465,7);
drawmat(zhe16H,16,530,465,7);
drawmat(tian16H,16,550,465,7);
drawmat(xue16H,16,565,465,7);
drawmat(ke16H,16,580,465,7);
}
void draw(void)/*画出四周的墙*/
{
if(color==15)
color=0;
setcolor(++color);
setlinestyle(SOLID_LINE,0,1);
for(i=30;i=600;i+=10)
{
rectangle(i,40,i+10,49);
rectangle(i,451,i+10,460);
}
for(i=40;i450;i+=10)
{
rectangle(30,i,39,i+10);
rectangle(601,i,610,i+10);
}
}
void prscore(void)
{/* 打印游戏分数 */
char str[10];
setfillstyle(SOLID_FILL,YELLOW);
bar(50,10,200,30);
setcolor(6);
settextstyle(0,0,2);
sprintf(str,"score:%d",score);
outtextxy(55,15,str);
}
void gameover(void)
{
cleardevice(); /* 清屏函数 */
for(i=0;isnake.node;i++)/* 画出蛇死时的位置 */
{
setcolor(snake.color[i]);
rectangle(snake.x[i],snake.y[i],snake.x[i]+10,snake.y[i]+10);
}
prscore(); /* 显示分数 */
draw();
showword();
settextstyle(0,0,6);
setcolor(7);
outtextxy(103,203,"GAME OVER");
setcolor(RED);
outtextxy(100,200,"GAME OVER");
}
void gameplay(void)/* 玩游戏的具体过程 */
{
int flag,flag1;
randomize();
prscore();
gamespeed=50000;
food.yes=0;/* food.yes=0表示屏幕上没有食物 */
snake.life=1;/* snake.life=1表示蛇是活着的 */
snake.direction=4;/* 表示蛇的初始方向为向右 */
snake.node=2; /* 蛇的初始化为两节 */
snake.color[0]=2; /*两节蛇头初始化为绿色*/
snake.color[1]=2;
snake.x[0]=100;snake.y[0]=100;
snake.x[1]=110;snake.y[1]=100;
food.color=random(15)+1;
while(1)
{
while(1)
{
if(food.yes==0) /* 如果蛇活着 */
{
while(1)
{
flag=1;
food.yes=1;
food.x=random(56)*10+40;
food.y=random(40)*10+50;
for(i=0;isnake.node;i++)
{
if(food.x==snake.x[i]food.y==snake.y[i])
flag=0;
}
if(flag) break;
}
}
if(food.yes)
{
setcolor(food.color);
rectangle(food.x,food.y,food.x+10,food.y+10);
}
for(i=snake.node-1;i0;i--)
{
snake.x[i]=snake.x[i-1];
snake.y[i]=snake.y[i-1];
}
switch(snake.direction)
{
case 1: snake.y[0]-=10;break;
case 2: snake.y[0]+=10;break;
case 3: snake.x[0]-=10;break;
case 4: snake.x[0]+=10;break;
}
for(i=3;isnake.node;i++)
{
if(snake.x[i]==snake.x[0]snake.y[i]==snake.y[0])
{
gameover();
snake.life=0;
break;
}
}
if(snake.x[0]40||snake.x[0]590||snake.y[0]50||snake.y[0]440)
{
gameover();
snake.life=0;
}
if(snake.life==0)
break;
if(snake.x[0]==food.xsnake.y[0]==food.y)/*蛇吃掉食物*/
{
setcolor(0);
rectangle(food.x,food.y,food.x+10,food.y+10);
snake.x[snake.node]=-20;
snake.y[snake.node]=-20;
snake.color[snake.node]=food.color;
snake.node++;
food.yes=0;
food.color=random(15)+1;
score+=10;
prscore();
if(score%100==0score!=0)
{
for(i=0;isnake.node;i++)/* 画出蛇 */
{
setcolor(snake.color[i]);
rectangle(snake.x[i],snake.y[i],snake.x[i]+10,snake.y[i]+10);
}
sound(200);
delay(50000);delay(50000);delay(50000);
delay(50000);delay(50000);delay(50000);
nosound();
gamespeed-=5000;
draw();
}
else
{
sound(500);
delay(500);
nosound();
}
}
for(i=0;isnake.node;i++)/* 画出蛇 */
{
setcolor(snake.color[i]);
rectangle(snake.x[i],snake.y[i],snake.x[i]+10,snake.y[i]+10);
}
delay(gamespeed);
delay(gamespeed);
flag1=1;
setcolor(0);
rectangle(snake.x[snake.node-1],snake.y[snake.node-1],
snake.x[snake.node-1]+10,snake.y[snake.node-1]+10);
if(kbhit()flag1==1)/*如果没按有效键就重新开始循环*/
{
flag1=0;
key=bioskey(0);
if(key==esc)
exit(0);
else if(key==upsnake.direction!=2)
snake.direction=1;
else if(key==downsnake.direction!=1)
snake.direction=2;
else if(key==leftsnake.direction!=4)
snake.direction=3;
else if(key==rightsnake.direction!=3)
snake.direction=4;
}
}
if(snake.life==0)/*如果蛇死了就退出循环*/
break;
}
}
void main(void)
{
while(1)
{
color=0;
init();
cleardevice();
showword();
draw();
gameplay();
setcolor(15);
settextstyle(0,0,2);
outtextxy(200,400,"CONTINUE(Y/N)?");
while(1)
{
key=bioskey(0);
if(key==Y||key==n||key==esc)
break;
}
if(key==n||key==esc)
break;
}
closegraph();
}
c语言作业,以下四种水果,1.苹果2.梨3.桔子.4.芒果,它们的单价分别是2.0元/公
//希望我的回答对你的学习有帮助
#includestdio.h
#includewindows.h
int main(){
double weight,pay,price;
int num;
printf("请输入水果编号、重量：");
scanf("%d%lf",num,weight);
switch(num){
case 1:price=2;break;
case 2:price=2.5;break;
case 3:price=3;break;
case 4:price=4.5;break;
default:printf("你输入的编号有误！\n");exit (0);
}
pay=weight*price;
printf("应付款：%.2lf\n",pay);
return 0;
}
简单的C语言题目 水果库存题
流程图我就不画了，大致流程：开始- 定义商店结构变量-调用入库函数录入库存商品信息-循环调用打印商品信息的函数及购买函数，显示库存商品菜单，用户输入购买信息完成购买
-单个水果购买数量不足，购买失败重新选择。
-总水果数量不足，提示关店结束程序。
#include stdio.h
#include string.h
#define goodsNum 10//商品总类最大个数
struct shop
{
char goodsName[goodsNum][11];
int goods[goodsNum];
int sum;
}sp;
int gn=0;//实际入库的商品总类个数
void storage();//入库函数
void updateSum();//更新总数
void printfGoods();//展示库存信息
int buy();//购买函数，返回1购买成功，返回0超出商品库存
int main()
{
storage();
while(1)
{
printfGoods();
if(sp.sum==0)
{
printf("所有水果已售空，关店休息！\n");
return 0;
}
if(buy())
printf("购买成功！\n");
}
return 0;
}
void printfGoods()
{
int i;
printf("--当前库存信息--\n");
printf("编号 名称 个数个\n");
for(i=0;ign;i++)
printf("%d、 %s %d个\n",i+1,sp.goodsName[i],sp.goods[i]);
}
void updateSum()
{
int i;
sp.sum=0;
for(i=0;ign;i++)
sp.sum=sp.sum+sp.goods[i];
}
void storage()
{
char name[10];
int n;
printf("--商品入库--\n");
while(1)
{
printf("请录入商品%d的名称及个数（名称不超10个字符，输入0结束录入）：",gn+1);
scanf("%s",name);
if(name[0]=='0' name[1]==0)
break;
scanf("%d",n);
strcpy(sp.goodsName[gn],name);
sp.goods[gn]=n;
gn++;
}
updateSum();
}
int buy()
{
int id,n;
printf("请输入要购买的商品编号及数量：\n");
scanf("%d%d",id,n);
if(nsp.goods[id-1])
{
printf("购买失败，数量超出库存！\n");
return 0;
}
sp.goods[id-1]=sp.goods[id-1]-n;
updateSum();
return 1;
}
求C语言编程实例电脑版切水果源代码
切水果不可能是C语言版用C语言图形函数画出水果的用C语言图形函数画出水果，C语言还做不到那么高级的图形处理用C语言图形函数画出水果，一般是Android工程的JAVA代码，当然底层可能有部分C/C++代码。
用c语言怎么写一个苹果?
C语言的苹果代码具体如下
一、代码一
#includestdio.h
int t;//定义全局变量，用于循环
char tab[] = {//储存用于输出图形的数组
0,1,1,0,0,1,1,0,
1,0,0,1,1,0,0,1,
1,0,0,0,0,0,0,1,
1,0,0,0,0,0,0,1,
0,1,0,1,1,0,1,0,
0,0,1,0,0,1,0,0,
};
void main()
{
for (t = 0; t 49; t++)
{
if (t % 8 == 0)//上面数组每8个一行，则在此处每8个换行
printf("\n");
if (tab[t] == 0)//数组元素为0，则输出空格
printf(" ");
else//数组元素不为零，则输出*号
printf("*");
}
}
二、代码二
#includestdio.h
int main()
{
int i,j,k;
for(i=1;i=4;i++) //先打印上边的四行
{
for(j=1;j=4-i;j++) //控制要打印的空格数量
printf(" ");
for(k=1;k=2*i-1;k++) //控制要打印的星号数
printf("*");
printf("\n");
}
for(i=1;i=3;i++)
{
for(j=1;j=i;j++) //控制要打印的空格数
printf(" ");
for(k=1;k=7-2*i;k++) //控制要打印的星号数
printf("*");
printf("\n");
}
return 0;
}
输出结果如图所示
扩展资料：
用C语言写苹果等图形代码的注意事项
1、我们知道 ’ \n ’ 在C语言中是转义字符，是 ’ 跳转到下一行 ’ 的意思，而在 ’ \n ’ 后加上 ’ \ ’ 则是告诉电脑：下一行代码是这一行的延续（用于分行写代码时）。
2、在使用 ’ \n\ ’ 之后，’ \n\ '后不允许再出现字符（包括空格）。
3、每行代码的第一个字符前面的空白部分必须用 ’ 空格 ’ 填充，不能使用 ’ TAB ’ 键。
4、我们注意到前三幅图中的第七行代码中，有三个连续 ’ \ ’ ，在C语言中 ’ \ ’ 表示输出一个 ’ \ ’ ， 所以前两个 ’ \ ’ 表示让计算机输出 ’ \ ’ ，而第三个 ’ \ ’ 则构成转义字符 ’ \n ’ 。 同理， 第四幅图中的 ’ %% ’ 是为了输出 ’ % ’ 。
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