vb.net如何随机数 vb随机数字的代码

vb.net中产生三位正整数的随机数的程序写法

'项目：VB中产生在一定正整数范围内的不重复的随机数'作者：qq15495835Private Sub Command1_Click() Max = 100 '随机数上限值 Min = 1 '随机数下限值 Amount = 10 '产生号码数量(数量值应小于随机数上限值-随机数下限值)否则会产生死循环 ReDim a(Amount) Randomize For i = 0 To Amount a(i) = Int((Max - Min + 1) * Rnd + Min) For j = 0 To i If i j And a(i) = a(j) Then i = i - 1 Next Next Text1 = Join(a, vbCrLf)End Sub'请采纳参考！谢谢！

VB.NET中怎么实现每单击一次按钮，文本框就多出现一个1-13的随机数字？

Dim n As Integer, b As Integer, a(13) As Integer

Private Sub Command1_Click()

If b 5 Then

b = b + 1

x = Int(n * Rnd()) + 1

Text1.Text = Text1.Text a(x) " "

a(x) = a(n)

n = n - 1

Else

Call Form_Load

End If

End Sub

Private Sub Form_Load()

Randomize

n = 13: b = 0

For i = 1 To 13

a(i) = i

Next i

Text1.Text = ""

End Sub

怎么用vb.net随机产生5个不同的数，范围1-33，求帮忙改一下

Private Sub Command1_Click()

Dim num(6) As Integer

Dim i As Integer, j As Integer

Dim tmp As Integer

Randomize '防止每次生出随机数一样

For i = 0 To 5

num(i) = Int(Rnd * 53) + 1

Next

PrintNum "新生成vb.net如何随机数的6个随机数为vb.net如何随机数：", num()

For i = 0 To 5

For j = 0 To 5

If num(j) num(j + 1) Then

tmp = num(j)

num(j) = num(j + 1)

num(j + 1) = tmp

End If

Next

Next

PrintNum "排序后vb.net如何随机数的6个随机数为vb.net如何随机数：", num()

End Sub

vb.net怎样生成随机数

Dim a As Integer = CInt(Int((9999 - 1000 + 1) * Rnd() + 1000))

注vb.net如何随机数：randomvalue = CInt(Int((upperbound - lowerbound + 1) * Rnd() + lowerbound))

这里vb.net如何随机数，upperbound 是此范围内最大vb.net如何随机数的数vb.net如何随机数，lowerbound 是此范围内最小的数。

vb.net产生随机数

方法名称：next()；功能描述：返回一个0~2147483647之间的整数

方法名称：next(i)；功能描述：返回一个0~i之间的整数

方法名称：next(i，j)；功能描述：返回一个i~j之间的整数

方法名称：Nextdouble()；功能描述：返回一个0~1之间的随机小数

================

使用方法：

Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click

Dim rand = New System.Random()

MsgBox(rand.next().ToString())

End Sub

==========================

产生N个不同数的话，我给你个我写的VB的代码，你稍微改下：

产生0-10的数：

Private Sub Command1_Click()

Randomize

Dim a(10) As Long

n = 10

For i = 0 To n

a(i) = Int(Rnd() * (n + 1))

For j = 0 To i - 1

If a(i) = a(j) Then

i = i - 1

Exit For

End If

Next

Next

For i = 0 To n

Print a(i)

Next

End Sub

请问在vb.net中如何实现随机取数??

Dim k() As Integer = New Integer() {1, 2, 3, 4, 5, 6}

Dim p1 As Integer

Random r = new Random();

int p1 = k(r.Next(5)) '随机出现0~5之间的数。

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