正文
asp.net core mvc中自定义ActionResult
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在GitHub上有个项目，本来是作为自己研究学习.net core的Demo，没想到很多同学在看，还给了很多星，所以觉得应该升成3.0，整理一下，写成博分享给学习.net core的同学们。
项目名称：Asp.NetCoreExperiment
项目地址：https://github.com/axzxs2001/Asp.NetCoreExperiment
asp.net core mvc的模板中返回前端时可以用IActionResult的子类，来区分不同的返回内容，那怎么来实现自定义的ActionResult呢？
github代码如下：
https://github.com/axzxs2001/Asp.NetCoreExperiment/tree/master/Asp.NetCoreExperiment/Common/YamlResultDemo
首先引用一个三方包
PM> Install-Package YamlDotNet
YamlResult.cs
/// <summary>
/// YamlResul
/// </summary>
public class YamlResult : ActionResult
{
/// <summary>
/// Yaml值
/// </summary>
public object Value { get; private set; }
/// <summary>
/// 构造
/// </summary>
/// <param name="value"></param>
public YamlResult(object value)
{
Value = value;
}
/// <summary>
/// Result执行者
/// </summary>
/// <param name="context">上下文</param>
/// <returns></returns>
public override async Task ExecuteResultAsync(ActionContext context)
{
var services = context.HttpContext.RequestServices;
var executor = services.GetRequiredService<IActionResultExecutor<YamlResult>>();
await executor.ExecuteAsync(context, new YamlResult(this));
}
}
YamlResultExecutor.cs
/// <summary>
/// YamlResult执行者
/// </summary>
/// <typeparam name="T"></typeparam>
public class YamlResultExecutor<T> : IActionResultExecutor<T> where T : YamlResult
{
/// <summary>
/// 执行
/// </summary>
/// <param name="context">上下文</param>
/// <param name="result">值</param>
/// <returns></returns>
public async Task ExecuteAsync(ActionContext context, T result)
{
var serialize = new YamlDotNet.Serialization.Serializer();
var valueString = serialize.Serialize(result.Value);
// 把对象转成yaml字符串，用Response返回
context.HttpContext.Response.ContentType = "Content-Type: text/html; charset=utf-8";
await context.HttpContext.Response.WriteAsync(valueString);
}
}
TestController.cs中调用代码
[HttpGet]
public IActionResult Get()
{
return new YamlResult(new
{
Data = new { a = , B = "bbb", C = DateTime.Now, d = new string[] { "a", "b", "c" } },
Status = true,
Message = "成功"
});
}
运行结果：
